help asap The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g)…

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The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) = H2(g) +12(8) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.319 M HI, 4.27×10-2 M H, and 4.27×10-2 M 12. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.40×102 mol of 12() is added to the flask? [H2] – [12] =