# Two capacitors are connected to each other and the battery is removed. The voltage across each…

Two capacitors are connected to each other and the battery is

removed. The voltage across each capacitor is 5.5 volts. V = V1 =

V2 = 5.5 V. The capacitance of C1 = 1.0 x 10 ^-6 F and the

capacitance of C2= 2.0 x 10 ^-6 F. What is the charge on each

capacitor? If the gap between the plates of C1 if filled with

paraffin (dielectric constant K=2.2) what is the new charge on each

capacitor and what is the new voltage across each capacitor? [The

total charge is conserved and the voltage across the first

capacitor is still equal to that across the second capacitor.]

Calculate the total stored potential energy of the charged

capacitors before and after the paraffin was added. Was there a

loss or gain of potential energy when the dielectric was inserted?

What % of the original potential energy was gained or lost?