Two capacitors are connected to each other and the battery is removed. The voltage across each…

Two capacitors are connected to each other and the battery is
removed. The voltage across each capacitor is 5.5 volts. V = V1 =
V2 = 5.5 V. The capacitance of C1 = 1.0 x 10 ^-6 F and the
capacitance of C2= 2.0 x 10 ^-6 F. What is the charge on each
capacitor? If the gap between the plates of C1 if filled with
paraffin (dielectric constant K=2.2) what is the new charge on each
capacitor and what is the new voltage across each capacitor? [The
total charge is conserved and the voltage across the first
capacitor is still equal to that across the second capacitor.]
Calculate the total stored potential energy of the charged
capacitors before and after the paraffin was added. Was there a
loss or gain of potential energy when the dielectric was inserted?
What % of the original potential energy was gained or lost?