# What will my heat gained by the calorimeter be? and total heat gained? Also do I…

What will my heat gained by the calorimeter be? and total heat
gained? Also do I represent heat loss of metal as
negative?
Part 2: Determining the Specific Heat Capacity of an Unknown Metal Data Trial 2 Trial 1 4.62g Mass of calorimeter Mass of calorimeter + water Mass of metal 102.35 g 81.63 g 22.1 C Initial temperature of water in calorimeter Initial temperature of metal 98.8 C Final temperature of calorimeter + added metal 27.5 C Calculations Trial 2 Trial 1 97.73 g Mass of water in calorimeter (mcw) Mass of added hot metal (MHM) 81.63 g Temperature change of cool water (Qcw) 5.4 C Temperature change of hot metal (ATHM) -71.3 C Heat gained by the cool water (Qcw) 2.2×1013 J (Show calculations for one trial) Qcw=mx Specific Heat Capacity Water x Chng. C.W. Qcw= 97.73(4.184)(5.4)=2208. J (2 S.f) Heat gained by the calorimeter (Qcal) (Show calculations for one trial) Total heat gained (Qgained) Heat lost by hot metal (QHM) -2.2×10^3 J Heat capacity of metal (Cmetal) 0.38 J/gC (Show calculations for one trial) -2.2×10^3=81.639 x S x-71.3 2.2×1043/5.82×10^3=0.378